OK, let's see if I've got this.

If you have an extension like a very elongated crowsfoot, i.e., a bar with a female 1/2" drive socket on one end, and a male on the other end, both perpindicular to the shaft of the bar, like a breaker bar with a female socket on the handle end. I insert a torque wrench on the female end, and a socket to the work on the male end. The bar is 1' from center to center of the drives. I put the t/wrench on in line with the ext. bar and apply 50 ftlbs to a .5" radius to contact fastener. How much torque did I apply to the fastener? Now I put the t/wrench on at close to a right angle to the ex. bar (actually at a smaller angle to put the handle pivot of the t/wrench at the same distance from the center of the fastener as the female extension bar end) and apply 50 ftlbs on the wrench scale. What did I do to the fastener this time? Same thing? Different? I think it's the same, and I think it's 600ftlbs, but I get confused easy when I do the math in my head.