Very good gentlemen. So any body have a good formula?

I came up with this one, but is really difficult to post hear so I will just go through verbally.

I took extension length c/c and divided that into twelve, (ratio for ft lbs.) then
inverted and multiplied that times the specified torque value. I then took that and subtracted it from the specified value to get my actual torque wrench setting. I think I said that right, just doesn't look the same as my formula on paper.

Theory was to figure the ratio advantage of the extension. and subtract that from the torque value, Now I have successfully eliminated the uneccessary variable right?

If the torque value was 50 ftlbs to be applied, and I had a 6" ext. My calc would be 12 divided by 6 = 2. invert and multiply times 50 and I would get 25 50 minus 25 is the corrected value right? So that was a round number. I need 45 ftlbs and have a 2.5 in ext. 12divided by 2.5=4.8 invert and multiply times 45 =9.375 subtract that from 45 for a crrected value of 35.625 This would be the striaght line calculation for the extension. What would it be for various angles? My calculator has the sin cos stuff so if neccesary for the formula so be it.

Did I over simplify this? My number came out only slightly different than using the formula with torque wrench length, but I beleive mine to be more accurate in the straight line use of the extension.

What would the formula be if I had to reach my fastener at an angle other than straight line? or for that the formula using any degree of angle of the extension. We must keep in mind the proper angle of pull in respect to the angle of extension also right. I mean if the extension is at 90 and you pull in a direction parrallel to the extension, the advantage would change if you pulled directly toward the center of rotation of the fastener right?

I believe the mud is getting clearer <img src="/forums/images/graemlins/confused.gif" alt="" />

Im not too sure on the moments of the dia of the bolt as in the diagram above, but will contemplate. But as rebutted, the force on the torque wrench wouldn't neccissarily know what size bolt head or socket head was being used right? Yet for some reason I beleive there is more to it than the stated obvious. Maybe not enough for us car mechanics to concern urselves about, but then again that would apply to my first question of the formula with the handle length.

Just hoping to get a better understanding of the applied torque and proper, methods of use, and calculations.