Question is: What is the formula to figure the amount of torque (rotating force) needed to give 20 ft lbs at the bolt to be tightened, with the torque applied at the open end of the combination wrench.
Okay Magoo, let's work it backward.You want 20 ft/lb on the bolt, right? There's only 2 variables left: force and distance. Now if my extension is .5 feet and t-wrench effective lentgh is 2 foot, then the lever is 2.5 feet long. How hard do I pull on a 2.5 foot lever to get 20 ft/lbs on bolt? 8 lbs, right? 2.5 X 8 = 20. Now I need to figure out how to get an accurate 8 lbs pull (NOT ft/lbs) on the end of my 2.5 foot lever (t-wrench + extension). The only gauge available is the torque scale on the t-wrench (handy eh?). 8 lbs pull on a 2 foot t-wrench yields a reading of 16 ft/lbs on the scale, so, pull the torque wrench with the extension on till it reads 16 ft/lbs and your bolt will be torqued accurately to 20 ft/lbs. Let's try it with a 1 foot effective length t-wrench + .5 foot extension. Lever length is 1.5 feet, so,1.5 X 13.33 = 20 . I need 13.33 lbs pull on a 1.5 foot lever to get 20 ft/lbs, right? Okay it's easy this time,to get 13.33 lbs pull on a 1 foot effective length t-wrench, you pull till the gauge reads 13.33 ft/lbs. So put the extension on your 1 foot t-wrench and pull till the gauge reads 13.33 ft/lbs and your bolt will be torqued accurately to 20 ft/lbs. Just think, pull, in lbs times lever length, in feet gives you accurate torque in ft/lbs on your bolt. I guarant....aw heck just check it out. <img src="/forums/images/graemlins/lol.gif" alt="" /> <img src="/forums/images/graemlins/lol.gif" alt="" /> <img src="/forums/images/graemlins/lol.gif" alt="" />
Scotty