It'll probably work, can you estimate the length of throw, and where the sliding collar starts, relative to the end of the input retainer snout?
You could run a longer body to the throwout bearing holder. The input retainer snout you pulled -- is it the same OD? How do the retainers that you have vary, exactly (clearly length, but what else)?
Randii
Randii, OK I need to find the throwout bearing throw length before I can figure this out so I should probbaly back up a second.
Lets start with the pilot bushing. Here is what my crank looks like now. I am ASSUMING the old pilot bushing is still in there.
I can gouge it pretty easily with a little hammer tap and punch so I am assuming that is not the crank.
It is however very stuck and there is no internal overlap to use a puller or do the grease trick. Not sure how I can get that thing out of there.
Assuming this is the pilot, I calculated i will need a pilot that is .43"ID x 1.25"OD x 2" long
Next would be pressure plate ratio. According to those articles on Novak's site, since my pressure plate is ~9.5" they suggest my pressure plate ratio as approximately 4.5 to 1.
I looked at my pressure plate and noticed the fulcrum is a thin rod bent in a circle that is held in between those pins and the stamped section after it. It also seems like the end of the "fingers" are right at the outside of the circle near the springs.
I measured the long arm at 2.75" and the short arm at about 1" so wouldn't that make my ratio 2.75 to 1?????? Why would the Novak site suggest 4.5 to 1?
The Novak site says the pressure plate must move .10" to .12" in order to provide an air gap of .030" to .050". So If I take .12" and times the pressure plate ratio (2.75:1) I get .33". They suggest I add in a freeplay amount of .06" (1/16") to bring the total amnount the release bearing moves to .39"
My clutch fork is even on both sides. It is a 2:1 ratio since the release bearing is right in the middle. So the slave rod will need to go .78" in order to move the release bearing .39"
Seem somewhat accurate???
My slave cylinder is .75" bore and master is .625 (5/8") bore. This would meen I have a hydraulic ratio of 0.833
To get the slave to move .78" I would have to move the master .93 or about 1" which is about half the stroke so I should be OK there.
The stock zu slave cylinder is .875" (7/8") so it is definetly true what you were saying that the slave is often different than the master.
Last thing is the distance from slave mounting surface to the clutch fork and I measured 3.75" This worries me a bit and I think I might have to weld in an extension to the shift fork or put a spacer between the shift "block" and clutch fork. I don't think it would be a good idea to put that much leverage on the cylinder.
![[Linked Image]](http://berisford.net/uploads/cpom/projectpup/17/07.jpg)
My slave brasss fitting stripped so I need to get another one and test what I guessed above but here are a few pics from messing around. I think the .75" bore air slave cyl I have might work out fine.
![[Linked Image]](http://berisford.net/uploads/cpom/projectpup/17/04.jpg)
![[Linked Image]](http://berisford.net/uploads/cpom/projectpup/17/05.jpg)
![[Linked Image]](http://berisford.net/uploads/cpom/projectpup/17/06.jpg)