Gary,
You have to look at it from the input (drive line) instead of the output (wheels).
What happens is the front end gets turned slightly faster by the drive line where the rear end turns slightly slower.
The front and rear drivelines try and turn at the same speed so the front end will turn 4.11 times with 1 full rotation of the drive line where the rear turns only 4.10 times with 1 full rotation of the driveline.
Thus the front is pulling the rear end because it has rotated 0.01 times farther.
Logansportage <img src="/forums/images/graemlins/patriot.gif" alt="" />
Your logic about the front pulling is correct, but the ratio logic isn't. Re-read what I said earlier. The error in your logic is here:
...the front end will turn 4.11 times with 1 full rotation of the drive line where the rear turns only 4.10 times with 1 full rotation of the driveline.
The differentials are not stepping
up the speed, they are stepping it
down. The easiest way to look at it is from what you put in, to what you get out.
Put one turn on each driveshaft and "measure" how far you go. If you accept the logic of my 1:1/100:1 example then extrapolate down to 4:1/5:1, then to 4.1:1/4.11:1, the 4.11 takes more "turns" of the input shaft (driveshaft) to go the same distance as a 4.1, and so the 4.11 is the "slower" ratio.
All part time transfer cases split the torque 50:50. The only ones that dont are the ones with clutch packs and other "active" parts in them such as differentials. The Sportage has none of this, and is strictly "old school" part time using gears for low range reduction and a chain to link the front and rear driveshafts.
